1、程序分析：可先用构建一个判断数组
2、实现代码：#include<stdio.h>#in罕铞泱殳clude<stdlib.h>即枢潋雳voidmain(){inti,j,m=30,n=80;boolword[30][80];for(i=0;i<m;i++){for(j=0;j<n;j++){if((i-m/2)*(i-m/2)*6+(j-n/2)*(j-n/2)<800&&(i-m/2)*(i-m/2)*6+(j-n/2)*(j-n/2)>550)word[i][j]=true;elseword[i][j]=false;}}for(i=0;i<m;i++){for(j=0;j<n;j++){if(word[i][j])printf("*");elseprintf("");}printf("\n");}system("pause");}