在Java中怎么四舍五入double

1、先将double根据 . 分解 Double dd = 0.08; Double ss = 1005.5; Double sss = dd*ss; System.out.println(sss); String[] st = sss.toString().split("\\."); System.out.println(st.length);

2、获取小数点后第一位String ne = st[0]; Integer neInt = Inte爿讥旌护ger.parseInt(ne); String ha = st[1].substring(0,1);//保留小数点后一位 Integer haInt = Integer.parseInt(ha); System.out.println(ne+":ha:"+ha+"neInt1:"+neInt);

3、开始四舍五入： Integer haInt = Integer.parseInt(ha); System.out.println(ne+":ha:"+ha+"neInt1:"+neInt); if(haInt>=5){ neInt+=1; } System.out.println(neInt);

4、完整代码：public class Dtx { public static void main(String[] args像粜杵泳) { Double dd = 0.08; Double ss = 1005.5; Double sss = dd*ss; System.out.println(sss); String[] st = sss.toString().split("\\."); System.out.println(st.length); String ne = st[0]; Integer neInt = Integer.parseInt(ne); String ha = st[1].substring(0,1);//保留小数点后一位 Integer haInt = Integer.parseInt(ha); System.out.println(ne+":ha:"+ha+"neInt1:"+neInt); if(haInt>=5){ neInt+=1; } System.out.println(neInt); }}